limsin2x的时尚分享

limsin2等于1。通过洛必达法则求解limsinx^2/x^2=lim2xcosx^2/2x=limcosx^2=1x→-2lim[(sinx)/x]=[sin(-2)]/(-2)=(sin2)/2=[sin(2×180°/π)]/2=(sin11.59°)/2=0.9093/2=0.45465应用条件在运用洛必达法则之前，首先......